Jawaban 1731130114 Riska Dwi Rahayu
1. Jawaban dari soal no 1
Hasil perkalian dot :
i.i = j.j = k.k = 1
= A.B = (2i + 6j – 9k).(4i – 2j + k)
= ( 2i.41 – 2i.2j + 2i.k + 6j.4i – 6j.2j + 6j.k – 9k.4i +
9k.2j – 9k.k )
= ( 8 – 0 + 0 + 0 – 12 + 0 – 0 + 0 – 9)
= (8 -12 – 9)
= -13
Hasil perkalian
silang :
i X i = j X j = k X k = 1
i X j = k j X i =
-k
j X k = i k X j =
-i
k X i = j k X i =
-j
= A X B = (2i + 6j –
9k) X (4i – 2j + k)
= ( (2.4)i X i – (2.2)i X j + (2.1)i X k + (6.4)j X i –
(6.2)j X j + (6.1)j X k – (9.4)k X i + (9.2)k X j – (9.1)k X k )
= 8.(0) – 4k – 2j – 24k – 12.(0) – 6i – 36j – 18i – 9.(0)
= – 4k – 24k – 2j – 36j – 6i – 18i
= – 24i – 38j – 28k
https://elektromagnetiksamodro.blogspot.com/2018/09/soal-1731130057-muhammad-yusuf-habibie.html
2. Jawaban dari no 2
2. Jawaban dari no 2
https://elektromagnetiksamodro.blogspot.com/2018/09/soal-1731130017-dhetax-erbian-pujangga.html